5 Steps to a 5 AP Chemistry (2010-2011 Edition) by John Moore, Richard H. Langley PDF

By John Moore, Richard H. Langley

ISBN-10: 0071624775

ISBN-13: 9780071624770

A ideal Plan for the right Score

We wish you to be triumphant in your AP* examination. That's why we've created this 5-step plan that can assist you research extra successfully, use your instruction time properly, and get your top ranking. This easy-to-follow advisor provide you with an entire overview of your AP direction, concepts to provide you the sting on try day, and lots of perform with AP-style try out questions. You'll sharpen your topic wisdom, advance your considering talents, and construct your test-taking self assurance with
* Full-length perform tests modeled at the actual try out * all of the phrases and ideas you want to comprehend to get your most sensible ranking * Your number of 3 personalized examine schedules--so you could decide the person who meets your wishes
The 5-Step Plan is helping you get the main from your examine time:
Step 1: arrange Your examine Program
Step 2: confirm Your Readiness
Step three: boost the Strategies
Step four: overview the Knowledge
Step five: construct Your Confidence

Topics include: Reactions and Periodicity, Stoichiometry, Gases, Thermodynamics, Spectroscopy, gentle, and Electrons, Bonding, Solids, drinks, and Intermolecular Forces, suggestions and Colligative houses, Kinetics, Equilibrium, Electrochemistry, Nuclear Chemistry, and natural Chemistry
Also includes: AP Chemistry perform exams

*AP, complex Placement application, and school Board are registered emblems of the varsity front exam Board, which used to be now not all in favour of the creation of, and doesn't advise, this product.

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Additional info for 5 Steps to a 5 AP Chemistry (2010-2011 Edition)

Sample text

Step 1: 2 NO2(g) → N2(g) + 2 O2(g) Step 2: 2 CO(g) + O2(g) → 2 CO2(g) Step 3: N2(g) + O2(g) → 2 NO(g) The above represents a proposed mechanism for the reaction of NO2 with CO. What are the overall products of the reaction? (A) (B) (C) (D) (E) N2 and O2 O2 and CO2 N2 and NO NO only NO and CO2 24 ❯ STEP 2. Determine Your Test Readiness 62. 84 × 106 − The reaction is 2ClO2(aq) + 2OH−(aq) → ClO2 (aq) − + ClO3 (aq) + H2O(l). What is the rate law for this reaction? (A) (B) (C) (D) (E) − 2 Rate = k[ClO2] [OH ] Rate = k[ClO2] 2 − Rate = k[ClO2] [OH ] − 2 Rate = k[OH ] Rate = k[ClO2][OH− ] Chapter 15 64.

38. A—Definition. 56. A—Molarity is moles per liter, and the moles are already known. 39. B—The d orbitals are less effectively shielded than the s orbitals. 57. 40 mol needed. 2+ 40. C—Mg becomes Mg . The element is N, which 3− can become N . 16 mol present. 24 mol Br to be added) − (1 mol MgBr2/2 mol Br ) Chapter 11 41. C—The iodine has five bonding pairs and one lone pair. 42. B—This is the only one with only single bonds. 43. C—Use VSEPR. 44. C—The only ionic bonds are the sodium compounds.

68. A—HBr is a strong acid. 69. D—The weak acid and weak base give a nearly neutral solution. 70. C—Only B and C are buffers. B is acidic and C is basic. 71. B—Only B and C are buffers. B is acidic and C is basic. − −9 1/2 −12 l/2 72. 0010 × 9 × 10 ) / = (9 × 10 ) 73. C—K = Ksp/Ka1Ka2 74. B—I yields no change. 3+ − 3 3 4 75. D—Ksp = [La ] [F ] = [x][3x] = 27x . Solve for x. 82. C—Alpha particles are the least penetrating, and gamma rays are the most penetrating. 83. C—Mass difference = 236 − 4(1) − 136 = 96.

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5 Steps to a 5 AP Chemistry (2010-2011 Edition) by John Moore, Richard H. Langley

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